document.write( "Question 863316: I have decided to hold a barbeque on June 21. If the probability that it will rain that day is 0.21 and the probability that the temperature will be less than 15 degrees is 0.14 and I have decided that I will not have the barbeque if it either rains or is colder than 15 degrees, what is the probaility that the barbeque will go ahead? I also know that in June the probability of the temperature being less than 15 degrees and it also raining is 0.13. Give your answer to 2 decimal places \n" ); document.write( "
Algebra.Com's Answer #520335 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! before knowing about the .13 probability \n" ); document.write( ".21+.14=.35 \n" ); document.write( "1-.35=.65 \r \n" ); document.write( "\n" ); document.write( "65% chance the BBQ will happen \n" ); document.write( "The .13 is for both things happening at the same time. \n" ); document.write( "I am not sure if you need to deal with that. The original \"or\" might deal with it. \n" ); document.write( "If not, it is 1-.13-.14-.21=.52=52%\r \n" ); document.write( "\n" ); document.write( "so it is either .65 or .52 \n" ); document.write( " that the bbq will happen. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |