document.write( "Question 863081: joe is 15 yrs younger then his brother. five years from now, three times his own age will equal twice his brother age how old is joe \r
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Algebra.Com's Answer #520259 by db12345(1)\"\" \"About 
You can put this solution on YOUR website!
Basically it is important to convert this into algebra so what I did was: \r
\n" ); document.write( "\n" ); document.write( "Let Joe's age = x
\n" ); document.write( "Let his brothers age = y
\n" ); document.write( "Now we write down all information given algebraically. \r
\n" ); document.write( "\n" ); document.write( "x=y-15 (joe is 15 years younger)\r
\n" ); document.write( "\n" ); document.write( "in 5 years time --> we add 5 to both sides\r
\n" ); document.write( "\n" ); document.write( "x+5=y-10\r
\n" ); document.write( "\n" ); document.write( "three times his own age will equal twice his brother age how old is joe --> multiply sides\r
\n" ); document.write( "\n" ); document.write( "3(x+5) = 2(y-10)
\n" ); document.write( "3x+15=2y-20
\n" ); document.write( "3x=2y-5
\n" ); document.write( "x=(2y-5)/3 (the \"/\" means divided by)
\n" ); document.write( "solving simultaneously
\n" ); document.write( "(2y-5)/3 =y-15 (multiply both sides by 3)
\n" ); document.write( "2y-5 = 3y-45
\n" ); document.write( "y=40
\n" ); document.write( "plug in for x
\n" ); document.write( "x= 40-15
\n" ); document.write( "x=25
\n" ); document.write( "Therefore Joe is 25 years old, feel free to double check by doing
\n" ); document.write( "3(25+5) = 90
\n" ); document.write( "2(40+5) = 90 \r
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