document.write( "Question 72741: Could someone show me how to solve this? It'll help me study for me exam since I missed this section's notes and have no idea on how to do this problem. As always, help is always appreciated. Thank you. :)\r
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Algebra.Com's Answer #52025 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! (x)/(x-2)-(3x)/(4-x)=(-2)(x-6)/(x^2-6x+8)\r \n" ); document.write( "\n" ); document.write( "------------ \n" ); document.write( "If you factor the last denominator you get (x-4)(x-2) \n" ); document.write( "---------- \n" ); document.write( "The 2nd fraction can be re-written as +(3x)/(x-4) \n" ); document.write( "-------- \n" ); document.write( "Now the problem looks like: \n" ); document.write( "(x)/(x-2)+(3x)/(x-4)=(-2)(x-6)/[(x-4)(x-2)] \n" ); document.write( "-------\r \n" ); document.write( "\n" ); document.write( "The least common multiple (lcm) of the denominators is (x-2)(x-4) \n" ); document.write( "-------- \n" ); document.write( "Multiply thru by the lcm to get rid of the denominators. \n" ); document.write( "----- \n" ); document.write( "[x(x-4)] + (3x)(x-2) = -2(x-6)\r \n" ); document.write( "\n" ); document.write( " x^2-4x + 3x^2-6x = -2x+12\r \n" ); document.write( "\n" ); document.write( " 4x^2 - 8x -12 = 0\r \n" ); document.write( "\n" ); document.write( " x^2 -2x -3 = 0 \n" ); document.write( "(x-3)(x+1)=0 \n" ); document.write( "x=3 or x=-1 \n" ); document.write( "======= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |