document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=863163>Question 863163</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangular piece of cardboard has a length that is 3 inches longer than the width. A square 1.5 inches on a side is cut from each corner. the sides are then turned up to form an open box with a volume of 162 cubic inches. find the dimensions of the original piece of cardboard. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #520248 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=520248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x for length<BR>\n" );
document.write( "y for width<BR>\n" );
document.write( "x=y+3<BR>\n" );
document.write( "The square of side size 1.5 inches being removed before folding the flaps means that height will be 1.5 inches.\r<BR>\n" );
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document.write( "Cutting the specified corner piece makes these variable dimensions for the base:<BR>\n" );
document.write( "(x-2(1.5)) and (y-2*1.5), meaning x-3 and y-3.  Using substitution for x as described means that the dimensions are:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x-3=%28y%2B3%29-3=highlight_green%28y%29 ALIGN=MIDDLE  ALT=\"x-3=%28y%2B3%29-3=highlight_green%28y%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > for the LENGTH of the base!<BR>\n" );
document.write( "and<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28y-3%29 ALIGN=MIDDLE  ALT=\"highlight_green%28y-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > for the WIDTH of the base.\r<BR>\n" );
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document.write( "Formulate the volume equation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%28y-3%29%281.5%29=162 ALIGN=MIDDLE  ALT=\"y%28y-3%29%281.5%29=162\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "-<BR>\n" );
document.write( "Simplify the volume equation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2-3y=162%2F1.5 ALIGN=MIDDLE  ALT=\"y%5E2-3y=162%2F1.5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2-3y-108=0 ALIGN=MIDDLE  ALT=\"y%5E2-3y-108=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Which is factorable:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28y%2B9%29%28y-12%29=0 ALIGN=MIDDLE  ALT=\"%28y%2B9%29%28y-12%29=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The sensible answer is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y=12%29 ALIGN=MIDDLE  ALT=\"highlight%28y=12%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > for the WIDTH.<BR>\n" );
document.write( "Finding x, x=y+3, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=12%2B3=15 ALIGN=MIDDLE  ALT=\"x=12%2B3=15\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x=15%29 ALIGN=MIDDLE  ALT=\"highlight%28x=15%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > for the LENGTH. </SPAN>\n" );
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