document.write( "Question 863143: A(5;5), B(-7;1), C(1;-7) are the vertices of triangle ABC which is an isosceles triangle. D(x;y) is a point in Quadrant 4 such that ABCD is a parallelogram. Calculate the area of ABCD correct to 3 decimal places. \n" ); document.write( "
Algebra.Com's Answer #520247 by mananth(16946)\"\" \"About 
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Distance between two points (AB)
\n" ); document.write( "x1 y1 x2 y2
\n" ); document.write( "
\n" ); document.write( "5 5 -7 1
\n" ); document.write( "d= \"sqrt%28%28y2-y1%29%5E2%2B%28x2-x1%29%5E2%29\"
\n" ); document.write( "d= \"sqrt%28%28%09%091%09-%095%09%29%5E2%09%2B%09%28%09-7%09-%095%09%29%5E2%09%29\"
\n" ); document.write( "d= \"sqrt%28%28%09%09-4%09%29%5E2%09%2B%09%28%09-12%09%29%5E2%09%29\"
\n" ); document.write( "d= \"sqrt%28%28%09%09160%09%29++%09%29\"
\n" ); document.write( "d= 12.65 \r
\n" ); document.write( "\n" ); document.write( "Distance between two points (BC)
\n" ); document.write( "x1 y1 x2 y2
\n" ); document.write( "
\n" ); document.write( "1 -7 -7 1
\n" ); document.write( "d= \"sqrt%28%28y2-y1%29%5E2%2B%28x2-x1%29%5E2%29\"
\n" ); document.write( "d= \"sqrt%28%28%09%091%09-%09-7%09%29%5E2%09%2B%09%28%09-7%09-%091%09%29%5E2%09%29\"
\n" ); document.write( "d= \"sqrt%28%28%09%098%09%29%5E2%09%2B%09%28%09-8%09%29%5E2%09%29\"
\n" ); document.write( "d= \"sqrt%28%28%09%09128%09%29++%09%29\"
\n" ); document.write( "d= 11.31 \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Distance between two points (AC)
\n" ); document.write( "x1 y1 x2 y2
\n" ); document.write( "
\n" ); document.write( "-7 1 5 5
\n" ); document.write( "d= \"sqrt%28%28y2-y1%29%5E2%2B%28x2-x1%29%5E2%29\"
\n" ); document.write( "d= \"sqrt%28%28%09%095%09-%091%09%29%5E2%09%2B%09%28%095%09-%09-7%09%29%5E2%09%29\"
\n" ); document.write( "d= \"sqrt%28%28%09%094%09%29%5E2%09%2B%09%28%0912%09%29%5E2%09%29\"
\n" ); document.write( "d= \"sqrt%28%28%09%09160%09%29++%09%29\"
\n" ); document.write( "d= 12.65
\n" ); document.write( "
\n" ); document.write( "Apply Herons formula for area of triangle\r
\n" ); document.write( "\n" ); document.write( "Area of triangle = \"sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29\"\r
\n" ); document.write( "\n" ); document.write( "where s = 1/2 perimeter
\n" ); document.write( "Perimeter36.61
\n" ); document.write( "s=18.31\r
\n" ); document.write( "\n" ); document.write( "Area =\"+sqrt%2818.31%2818.31-11.31%29%5E2%2B%2818.31-12.65%29%5E2%2B%2818.31-12.65%29%5E2%29\"
\n" ); document.write( "=31.004\r
\n" ); document.write( "\n" ); document.write( "area of parallelogram = 2 * area of triangle\r
\n" ); document.write( "\n" ); document.write( "=2*31.004
\n" ); document.write( "=62.008 sq. units
\n" ); document.write( "=
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