document.write( "Question 863131: A bank loaned 17,000, part of it at the rate of 6% per year and the rest at 14% per year. If the interest received in one year totaled 1500, how much was loaned at 6%? \n" ); document.write( "
Algebra.Com's Answer #520244 by mananth(16946)\"\" \"About 
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Part I 6.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 14.00% per annum ------------ Amount invested = y
\n" ); document.write( " 17000
\n" ); document.write( "Interest----- 1500.00
\n" ); document.write( "
\n" ); document.write( "Part I 6.00% per annum ---x
\n" ); document.write( "Part II 14.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 17000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "6.00% x + 14.00% y= 1500
\n" ); document.write( "Multiply by 100
\n" ); document.write( "6 x + 14 y= 150000.00 --------2
\n" ); document.write( "Multiply (1) by -6
\n" ); document.write( "we get
\n" ); document.write( "-6 x -6 y= -102000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 8 y= 48000
\n" ); document.write( "divide by 8
\n" ); document.write( " y = 6000
\n" ); document.write( "Part I 6.00% $ 11000
\n" ); document.write( "Part II 14.00% $ 6000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "11000 --------- 6.00% ------- 660.00
\n" ); document.write( "6000 ------------- 14.00% ------- 840.00
\n" ); document.write( "Total -------------------- 1500.00
\n" ); document.write( " \n" ); document.write( "
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