document.write( "Question 863135: How do I find the cos(5pi/12)?! The question says \"Use the sum or difference formula to determine the value of the trigonometric function\"\r
\n" ); document.write( "\n" ); document.write( "Thank you!
\n" ); document.write( "

Algebra.Com's Answer #520233 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
How do I find the cos(5pi/12)?! The question says \"Use the sum or difference formula to determine the value of the trigonometric function\"
\n" ); document.write( "***
\n" ); document.write( "cos(5π/12)=cos(2π/12+3π/12)=cos(π/6+π/4)
\n" ); document.write( "Identity: cos(x+y)=cosxcosy-sinxsiny)
\n" ); document.write( "cosx=cos(π/6)=√3/2
\n" ); document.write( "cosy=cos(π/4)=√2/2
\n" ); document.write( "sinx=sin(π/6)=1/2
\n" ); document.write( "siny=sin(π/4)=√2/2
\n" ); document.write( "cos(x+y)=√3/2*√2/2-1/2*√2/2=√6/4-√2/4=(√6-√2)/4
\n" ); document.write( "...
\n" ); document.write( "calculator check:
\n" ); document.write( "cos(5π/12)≈0.2588…
\n" ); document.write( "exact value=(√6-√2)/4≈0.2588…
\n" ); document.write( "
\n" );