document.write( "Question 863118: What would 2x + 3y = 6;x + y = 4 look like on a graph? Also explain how to do it, if possible! Thanks. \n" ); document.write( "
Algebra.Com's Answer #520209 by jim_thompson5910(35256)\"\" \"About 
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To graph 2x + 3y = 6, you need 2 points (since this is a straight line).\r
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\n" ); document.write( "\n" ); document.write( "Zero is usually a good goto number to work with since it greatly simplifies things, so I often plug 0 in for the variables and solve for the remaining variable. This will help you find the intercepts.\r
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\n" ); document.write( "\n" ); document.write( "So when x = 0, then 2x + 3y = 6 ---> 2(0)+3y = 6 ----> 3y = 6 ----> y = 2\r
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\n" ); document.write( "\n" ); document.write( "That means the y intercept is (0,2)\r
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\n" ); document.write( "\n" ); document.write( "Similarly, when y = 0, then 2x + 3(0) = 6 leading to 2x = 6 giving us x = 3\r
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\n" ); document.write( "\n" ); document.write( "The x-intercept is (3,0)\r
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\n" ); document.write( "\n" ); document.write( "Once you have the two intercepts (0,2) and (3,0), you plot them on the same coordinate axis. Then connect the two points.\r
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\n" ); document.write( "\n" ); document.write( "All of these steps are for graphing 2x + 3y = 6. You will need to repeat these steps over for x+y = 4\r
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\n" ); document.write( "\n" ); document.write( "Plotting both 2x + 3y = 6 and x+y = 4 on the same coordinate axis will help you see where they intersect/cross (if they do at all) which will lead to the solution to the system of equations. \n" ); document.write( "
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