document.write( "Question 72642: one man & 2 boys can do a piece of workin 12 days, which can also done by 3 men & 1 boy in 6 days. How long it would take for one alone man to complete the work? \n" ); document.write( "

Algebra.Com's Answer #52020 by stanbon(75887) $\"\"$ $\"About$

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one man & 2 boys can do a piece of workin 12 days, which can also done by 3 men & 1 boy in 6 days. How long it would take for one alone man to complete the work?
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\n" ); document.write( "I would appreciate seeing how your text or instructor does these problems.
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\n" ); document.write( "This is the best I can do with it:
\n" ); document.write( "(1m + 2b)(12 days) = 1 job
\n" ); document.write( "(3m + 1b)(6 days) = 1 job
\n" ); document.write( "-----------------
\n" ); document.write( "The 1st equation can be changed to read:
\n" ); document.write( "2(1m+2b)(12 days)(1/2) = 1 job
\n" ); document.write( "or
\n" ); document.write( "(2m+4b)(6 days) = 1 job
\n" ); document.write( "-------------
\n" ); document.write( "Then you can see that 3m+1b = 2m+4b
\n" ); document.write( "Then 1m=3b
\n" ); document.write( "or b=(1/3)m
\n" ); document.write( "-------------
\n" ); document.write( "Putting that into the 1st equation you can get:
\n" ); document.write( "(1m + 2(1/3)m)(12 days) = 1 job
\n" ); document.write( "[(5/3)m](12 days) = 1 job
\n" ); document.write( "Then: (3/5)[(5/3)m](12 days)(5/3)= 1 job
\n" ); document.write( "(1 m)(20 days) = 1 job
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\n" ); document.write( "So, 1 man can do the job in 20 days.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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