document.write( "Question 72744: Graph 0.5x^2-3 \n" ); document.write( "
Algebra.Com's Answer #52019 by rmromero(383)\"\" \"About 
You can put this solution on YOUR website!

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document.write( "Graph  0.5x^2-3\r
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document.write( "The graph looks like this.
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document.write( "\"graph+%28200%2C+200%2C+-4%2C+7%2C+-5%2C+6%2C+0.5x%5E2-3%29\"\r
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document.write( "Since we have a quadratic equation, we will find the vertex
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document.write( "       - b
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document.write( "   x = ____  where a = 0.5, b = 0 and c = -3
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document.write( "        2a\r
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document.write( "     = 0 / 2(0.5)
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document.write( "     = 0\r
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document.write( "Substitute x = 0 to 0.5x^2 - 3 to find y\r
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document.write( "      y = 0.5(0)^2-3
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document.write( "        = 0 - 3
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document.write( "        = -3\r
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document.write( "The vertex is located (0, -3)\r
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document.write( "Let y = 0 and solve for x to find the x - intercept\r
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document.write( "       0 = 0.5x^2 - 3
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document.write( "       3 = 0.5x^2         divide both sides by 0.5
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document.write( "       6 = x^2
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document.write( "± sqrt 6 = x  
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document.write( "   ± 2.4 = x  \r
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document.write( "   another points are (2.4, 0) and (-2.4, 0)\r
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document.write( "Plot the three points  \n" );
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