document.write( "Question 863014:
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document.write( "It took an airplane 2hours to fly 640mi against a headwind. The return trip with the wind took 1 1/3hours. Find the speed of the plane with no wind and the windspeed. \n" );
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Algebra.Com's Answer #520178 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "640=(R-W)*2 \n" ); document.write( "(R-W)=640/2=320 MPH AGAINST THE WIND. \n" ); document.write( "640=(R+W)*1.33 \n" ); document.write( "(R+W)=640/1.33 \n" ); document.write( "(R+W)=481.20 MPH WITH THE WIND. \n" ); document.write( "(481.20-320)/2=161.20/2=80.6 MPH IS THE WIND SPEED. \n" ); document.write( "320+80.6=400.6 AVERAGE SPEED OF THE PLANE WITH NO WIND. \n" ); document.write( "481.2-80.6=400.6 DITTO. \n" ); document.write( " |