document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=863055>Question 863055</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are 6 performers who will present their comedy acts this weekend. One of the performers insists on being the last stand-up comic of the evening. If this performer's request is granted, how many different ways are there to schedule the appearances?<BR>\n" );
document.write( "I tried to use the permutations formula where n=6(total performers) and r=5(other performers to arrange) <BR>\n" );
document.write( "I came up with 720 ways. <BR>\n" );
document.write( "Am I using the right formula? And steps?<BR>\n" );
document.write( "Help please. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #520166 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=520166\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the last place has been assigned the first place has only 5 choices<BR>\n" );
document.write( "5*4*3*2*1=20*6=120<BR>\n" );
document.write( "not <BR>\n" );
document.write( "6*5*4*3*2*1=720 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );