document.write( "Question 862943: Lewiston and Vernonville are 208 apart. A car leaves Lewiston traveling towards Vernonville, and another car leaves Vernonville at the same time, traveling towards Lewiston. The car leaving Lewiston average 10 miles per hour more than the other, and they meet after 1 hour and 36 minutes. What are average speeds of the cars?\r
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document.write( "The car leaving Lewiston averages __ mph.\r
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document.write( "The care leaving Vernonville averages __ mph. \n" );
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Algebra.Com's Answer #520156 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! In 1 hour and 36 minutes, the cars travel a total of 208 miles. \n" ); document.write( "(a + b)* 1 \n" ); document.write( "car a = b+10 (10mph faster) \n" ); document.write( "((b+10) + b)* 1 \n" ); document.write( "(2b+10)* 1.6 = 208 \n" ); document.write( "Divide each side by 1.6 \n" ); document.write( "2b + 10 = 130 \n" ); document.write( "Subtract 10 from each side \n" ); document.write( "2b = 120 \n" ); document.write( "b = 60 \n" ); document.write( ". \n" ); document.write( "If car b is traveling 60 mph, then car a is traveling 70 mph. \n" ); document.write( ". \n" ); document.write( "Let's plug this in to make sure we're correct. \n" ); document.write( "Car b travels 60 miles in the first hour, and 60*.6 in the partial hour - 96 miles total \n" ); document.write( "Car a travels 70 miles in the first hour, and 70*.6 in the partial hour - 112 miles total \n" ); document.write( "96 + 112 = 208 \n" ); document.write( "Success! \n" ); document.write( " |