document.write( "Question 863018: The sum of 4 times Ben's age and 5 times Neil's age is 128. Neil is 4 years older than Ben is.
\n" ); document.write( "Find each of their ages \n" ); document.write( "

Algebra.Com's Answer #520149 by ben720(159) $\"\"$ $\"About$

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Let N = Neil's age
\n" ); document.write( "Let N-4 = Ben's age, as neil is 4 years older
\n" ); document.write( " $\"4ben%2B5neil=128\"$
\n" ); document.write( " $\"4%28n-4%29%2B5n=128\"$
\n" ); document.write( "Distribute 4
\n" ); document.write( " $\"4n-16%2B5n=128\"$
\n" ); document.write( "Combine like terms
\n" ); document.write( " $\"9n-16=128\"$
\n" ); document.write( "Add 16 to both sides
\n" ); document.write( " $\"9n=144\"$
\n" ); document.write( "Divide both sides by 9
\n" ); document.write( " $\"n=16\"$
\n" ); document.write( "Neil is 16 years old, and, since Ben is 4 years younger, Ben is 12. \n" ); document.write( "

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