document.write( "Question 862840: Jess is running around a circular track, one lap every 40 seconds. Cameron is also running at a constant speed around the same track, but in the opposite direction. They meet every 15 seconds. How many seconds does it take Cameron to do one lap? \n" ); document.write( "

Algebra.Com's Answer #520148 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Jess is running around a circular track, one lap every 40 seconds.
\n" ); document.write( " Cameron is also running at a constant speed around the same track, but in the opposite direction.
\n" ); document.write( " They meet every 15 seconds. How many seconds does it take Cameron to do one lap?
\n" ); document.write( ":
\n" ); document.write( "let c = C's time to make one lap
\n" ); document.write( ":
\n" ); document.write( "In 15 sec, J had run 15/40 or 3/8 of a lap, therefore C has run 5/8 of a lap in the same time.
\n" ); document.write( "We can write the relationship: 3:5
\n" ); document.write( "An inverse relationship
\n" ); document.write( " $\"c%2F40\"$ = $\"3%2F5\"$
\n" ); document.write( "Cross multiply
\n" ); document.write( "5c = 3(40)
\n" ); document.write( "c = 120/5
\n" ); document.write( "c = 24 seconds is C's lap time
\n" ); document.write( " \n" ); document.write( "

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