document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=863024>Question 863024</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Helping with homework and this one has us stumped, any help is appreciated.\r<BR>\n" );
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document.write( "The length of a rectangle is 9 cm less than twice its width. If the area of the rectangle is 11cm squared, find the dimensions of the rectangle. \r<BR>\n" );
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document.write( "Many thanks,<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #520139 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=520139\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 2W - 9<BR>\n" );
document.write( "L*W = 11<BR>\n" );
document.write( "----<BR>\n" );
document.write( "W*(2W-9) = 11<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2W%5E2+-+9W+-+11+=+0 ALIGN=MIDDLE  ALT=\"2W%5E2+-+9W+-+11+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "(2W - 11)*(W + 1) = 0<BR>\n" );
document.write( "W = -1  Ignore<BR>\n" );
document.write( "----<BR>\n" );
document.write( "W = 11/2<BR>\n" );
document.write( "L = 2 </SPAN>\n" );
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