document.write( "Question 863010: Helping my child do her math and could use some help.\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 9 cm less than twice its width. If the area of the rectangle is 11cm squared, find the dimensions of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "Many thanks in advance,
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Algebra.Com's Answer #520136 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+w+\" = the width
\n" ); document.write( "\"+2w+-+9+\" = the length
\n" ); document.write( "------------------------
\n" ); document.write( "The area = ( length ) x ( width )
\n" ); document.write( "\"+A+=+%28+2w+-+9+%29%2Aw+\"
\n" ); document.write( "\"+11+=+%28+2w+-+9+%29%2Aw+\"
\n" ); document.write( "\"+2w%5E2+-+9w+=+11+\"
\n" ); document.write( "\"+2w%5E2+-+9w+-+11+=+0+\"
\n" ); document.write( "Use the quadratic formula
\n" ); document.write( "\"+w+=+%28+-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29+\"
\n" ); document.write( "\"+a+=+2+\"
\n" ); document.write( "\"+b+=+-9+\"
\n" ); document.write( "\"+c+=+-11+\"
\n" ); document.write( "\"+w+=+%28+-%28-9%29+%2B-+sqrt%28+%28-9%29%5E2+-+4%2A2%2A%28-11%29+%29%29+%2F+%282%2A2%29+\"
\n" ); document.write( "\"+w+=+%28+9+%2B-+sqrt%28+81+%2B+88+%29%29+%2F+4+\"
\n" ); document.write( "\"+w+=+%28+9+%2B-+sqrt%28+169+%29%29+%2F+4+\"
\n" ); document.write( "\"+w+=+%28+9+%2B+13+%29+%2F+4+\"
\n" ); document.write( "\"+w+=+11%2F2+\"
\n" ); document.write( "and
\n" ); document.write( "\"+2w+-+9+=+2%2A%2811%2F2%29+-+9+\"
\n" ); document.write( "\"+2w+-+9+=+11+-+9+\"
\n" ); document.write( "\"+2w+-+9+=+2+\"
\n" ); document.write( "------------------
\n" ); document.write( "The dimensions are:
\n" ); document.write( "5.5 cm x 2 cm
\n" ); document.write( "---------------
\n" ); document.write( "check:
\n" ); document.write( "\"+A+=+%28+2w+-+9+%29%2Aw+\"
\n" ); document.write( "\"+A+=+2%2A5.5+\"
\n" ); document.write( "\"+A+=+11+\" cm2
\n" ); document.write( "OK\r
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