document.write( "Question 862967: How many liters of water should be added to 20 L of a 30% acid solution to make a solution that is 10% acid? \n" ); document.write( "
Algebra.Com's Answer #520101 by Alan3354(69443)\"\" \"About 
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\n" ); document.write( "If I have a 25 mil test tube of 72% nitric acid and I want to reduce the concentration to 42%, how much water would I need to add ?
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\n" ); document.write( "w = ml of water
\n" ); document.write( "25*72 + 0*w = (25+w)*42
\n" ); document.write( "1800 = 42w + 1050
\n" ); document.write( "42w = 750
\n" ); document.write( "w = 125/7 ml
\n" ); document.write( "=~ 17.86 ml
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\n" ); document.write( "This is safe on paper.
\n" ); document.write( "If it's real liquids, add the acid to the water, not the water to the acid.
\n" ); document.write( "And don't drink any.
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