document.write( "Question 862945: At the beginning of a walk, Roberto and Juanita are 4.4 miles apart. If they leave at the same time and walk in the same direction, Roberto overtakes Juanita in 11 hours. If they walk towards each other, they meet in hour. What are their speeds?\r
\n" ); document.write( "\n" ); document.write( "Roberto's speed is __ mph.\r
\n" ); document.write( "\n" ); document.write( "Juanita's speed is __ mph.
\n" ); document.write( "

Algebra.Com's Answer #520082 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
At the beginning of a walk, Roberto and Juanita are 4.4 miles apart. If they leave at the same time and walk in the same direction, Roberto overtakes Juanita in 11 hours. If they walk towards each other, they meet in hour. What are their speeds?
\n" ); document.write( "Roberto's speed is __ mph.
\n" ); document.write( "Juanita's speed is __ mph.
\n" ); document.write( "***
\n" ); document.write( "Both walking in the same direction:
\n" ); document.write( "let x=distance Juanita travels
\n" ); document.write( "4.4+x=distance Roberto travels
\n" ); document.write( "speed=distance/travel time
\n" ); document.write( "Juanita's speed=x/11
\n" ); document.write( "Roberto's speed=(4.4+x)/11
\n" ); document.write( "...
\n" ); document.write( "Both walking toward each other:
\n" ); document.write( "let y=distance Juanita travels
\n" ); document.write( "4.4-y=distance Roberto travels
\n" ); document.write( "Juanita's speed=y/1=y
\n" ); document.write( "Roberto's speed=(4.4-y)/1=4.4-y
\n" ); document.write( "...
\n" ); document.write( "juanita's speed=x/11=y
\n" ); document.write( "x=11y
\n" ); document.write( "Roberto's speed=(4.4+x)/11)=4.4-y
\n" ); document.write( "=(4.4+11y)/11=4.4-y
\n" ); document.write( "=4.4+11y=48.4-11y
\n" ); document.write( "22y=44
\n" ); document.write( "y=2
\n" ); document.write( "4.4-y=2.2
\n" ); document.write( "Roberto's speed is 2.2 mph.
\n" ); document.write( "Juanita's speed is 2.0 mph.
\n" ); document.write( "
\n" );