document.write( "Question 862927: A student drove a distance of 125 miles at an average speed of 55 mph. How much faster would she have to drive on the return trip to save 30 minutes of driving time? \n" ); document.write( "
Algebra.Com's Answer #520073 by lwsshak3(11628)\"\" \"About 
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A student drove a distance of 125 miles at an average speed of 55 mph. How much faster would she have to drive on the return trip to save 30 minutes of driving time?
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\n" ); document.write( "let x=speed on the return trip to save 30 minutes of driving time
\n" ); document.write( "travel time=distance/speed
\n" ); document.write( "\"125%2F55-125%2Fx=1%2F2\"
\n" ); document.write( "LCD:55x
\n" ); document.write( "125x-55*125=55x/2
\n" ); document.write( "250x-13750=55x
\n" ); document.write( "195x=13750
\n" ); document.write( "x=70.51
\n" ); document.write( "speed on the return trip to save 30 minutes of driving time=70.51 mph
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