document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=862881>Question 862881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions and volume of the right circular cylinder of maximum volume inscribed in a sphere with a radius of 70 cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #520066 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39623)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=520066\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the positive x axis for radius and the positive y axis for height.  <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V=y%2Api%2Ax%5E2 ALIGN=MIDDLE  ALT=\"V=y%2Api%2Ax%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  The description is of the cross section through the middle of the cylinder.  This cross section uses a circle <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2=70%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2=70%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  You can reform the volume either in terms of x or in terms of y.  \r<BR>\n" );
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document.write( "Two choices.  Use a graphing tool or try derivative of V and maybe then resort to a graphing tool.  Where is derivative equal to zero?  Corresponding x?  Corresponding volume?\r<BR>\n" );
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document.write( "-unfinished-<BR>\n" );
document.write( "potentially posting and keeping unfinished. </SPAN>\n" );
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