document.write( "Question 862903: A train 450 metre long passes a car running at 35 km/hr opposite of direction in which train going in 6 seconds.calculate the speed of the train.
\n" ); document.write( "A. 61km/hr B.66km/hr C.101 km/hr D. 76 km/hr \n" ); document.write( "
Algebra.Com's Answer #520048 by ankor@dixie-net.com(22740)\"\" \"About 
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A train 450 metre long passes a car running at 35 km/hr opposite of direction in which train going in 6 seconds.
\n" ); document.write( "calculate the speed of the train.
\n" ); document.write( ":
\n" ); document.write( "Let s = the speed of the train
\n" ); document.write( "Change 6 sec to hrs: 6/3600 = 1/600 hrs
\n" ); document.write( "Change 450m to .45km
\n" ); document.write( ":
\n" ); document.write( "Distance = time * speed
\n" ); document.write( "\"1%2F600\"(s+35) = .450
\n" ); document.write( "s + 35 = 600*.450
\n" ); document.write( "s + 35 = 270
\n" ); document.write( "s = 270 - 35
\n" ); document.write( "s = 235 km/hr
\n" ); document.write( "I know this isn't even close to the given answers but that's what I get.
\n" ); document.write( "(If you meant 16 sec, B. would be close) \n" ); document.write( "
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