document.write( "Question 862774: Solve the equation sin^2x (plus) 2cos^2x=2.find the value of x \n" ); document.write( "
Algebra.Com's Answer #519947 by mananth(16946)\"\" \"About 
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\"sin%5E2%28x%29+%2B2cos%5E2%28x%29=2.\"\r
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\n" ); document.write( "\n" ); document.write( "\"1-cos%5E2%28x%29+%2B2cos%5E2%28x%29=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"+cos%5E2%28x%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "cosx =+/-1\r
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\n" ); document.write( "\n" ); document.write( "find the value of x
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