document.write( "Question 72718This question is from textbook Algebra:Structure and Method
\n" ); document.write( ": One computer can process a payroll in 60 minutes. A newer computer can process a payroll in 40 minutes. How long would it take to process the payroll if both computers worked together? \n" ); document.write( "
Algebra.Com's Answer #51994 by bucky(2189)\"\" \"About 
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One way to look at this is that in 1 minute the first computer does \"1%2F60\" of the job.
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\n" ); document.write( "And in the same time (1 minute) the new computer does \"1%2F40\" of the job.
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\n" ); document.write( "Stop and think about this a little. It'll help to make sense of this problem. If the first
\n" ); document.write( "computer runs for 30 minutes, how much of the job will it complete? Just multiply the 30 minutes
\n" ); document.write( "times \"1%2F60\" and you get \"30%2F60\" and this reduces to \"1%2F2\". So if it takes 60
\n" ); document.write( "minutes to complete the entire job, in 30 minutes it will be half done. Now think about what
\n" ); document.write( "we did to find this out. We multiplied the Rate which is \"1%2F60\" of the job per each
\n" ); document.write( "minute times the number of minutes. The same sort of thinking could be done for the second
\n" ); document.write( "(newer) computer. It completes \"1%2F40\" of the job each minute and by multiplying
\n" ); document.write( "this rate by the number of minutes it operates, you can determine how much of the job it
\n" ); document.write( "has completed. In the same 30 minutes as the first machine it would do
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\n" ); document.write( " \"%281%2F40%29%2A30+=+30%2F40+=+3%2F4\"
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\n" ); document.write( "or three-quarters of the job. Obviously, 30 minutes is too much time because the two machines
\n" ); document.write( "working together complete one-half plus three- quarters of the job in 30 minutes or more
\n" ); document.write( "than the entire job.
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\n" ); document.write( "So in each case let's multiply the elapsed time by the rate for the computer and when you
\n" ); document.write( "add the two computer outputs together it should equal 1 job done. In equation form this
\n" ); document.write( "becomes:
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\n" ); document.write( "\"%281%2F60%29%2At+%2B+%281%2F40%29%2At+=+1\"
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\n" ); document.write( "where t represents the time from the start when the two computers began working on the job.
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\n" ); document.write( "If you factor the t from the two terms on the left side of this equation you get:
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\n" ); document.write( "\"t%2A%28%281%2F60%29+%2B+%281%2F40%29%29+=+1\"
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\n" ); document.write( "A common denominator for the two fractions is 120. \"1%2F60+=+2%2F120\" and \"1%2F40+=+3%2F120\"
\n" ); document.write( "so that when you add these two you get \"%283%2B2%29%2F120+=+5%2F120%29\".
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\n" ); document.write( "The equation then becomes:
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\n" ); document.write( "\"t%2A%285%2F120%29+=+1\"
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\n" ); document.write( "You can now solve the equation either by dividing both sides by \"5%2F120\" or by multiplying
\n" ); document.write( "both sides by \"120%2F5\".
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\n" ); document.write( "When you do that the equation becomes:
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\n" ); document.write( "\"t+=+%28120%2F5%29\"
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\n" ); document.write( "and dividing 5 into 120 results in an answer of 24. So 24 minutes is the amount of processing
\n" ); document.write( "time it will take both machines working together to do 1 payroll.
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\n" ); document.write( "Hope this helps you to understand the problem a little better.
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