document.write( "Question 862759: Wilma drove at an average speed of 35 mi/h from her home in City A to visit her sister in City B. She stayed in City B 20 hours, and on the trip back averaged 45 mi/h. She returned home 42 hours after leaving. How many miles is City A from City B
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #519928 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Wilma drove at an average speed of 35 mi/h from her home in City A to visit her sister in City B. She stayed in City B 20 hours, and on the trip back averaged 45 mi/h. She returned home 42 hours after leaving. How many miles is City A from City B . \n" ); document.write( "*** \n" ); document.write( "Total driving time=42-20=22 hrs \n" ); document.write( "let x=travel time Wilma drove from home to city \n" ); document.write( "22-x=travel time Wilma drove from city to home \n" ); document.write( "distance=speed*travel time (equal in both directions) \n" ); document.write( ".. \n" ); document.write( "35x=45(22-x) \n" ); document.write( "35x=990-45x \n" ); document.write( "80x=990 \n" ); document.write( "x≈12.38 \n" ); document.write( "35x≈433 \n" ); document.write( "How many miles is City A from City B ? 433 \n" ); document.write( " |