document.write( "Question 862757: David has 280 yards of fencing to enclose a rectangular area. Find the demensions of the rectangle that maximize the enclosed area.What is the maximum area? \n" ); document.write( "
Algebra.Com's Answer #519927 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! David has 280 yards of fencing to enclose a rectangular area. Find the demensions of the rectangle that maximize the enclosed area.What is the maximum area? \n" ); document.write( "*** \n" ); document.write( "let x=width \n" ); document.write( "let y=length \n" ); document.write( "2x+2y=280 \n" ); document.write( "x+y=140 \n" ); document.write( "y=140-x) \n" ); document.write( ".. \n" ); document.write( "Area=xy=x(140-x)=140x-x^2 \n" ); document.write( "=-x^2+140x \n" ); document.write( "complete the square: \n" ); document.write( "=-(x^2-140x+4900)+4900 \n" ); document.write( "=-(x-70)^2+4900 \n" ); document.write( "This is an equation of a parabola that opens down with vertex at (70,4900) \n" ); document.write( "maximum area=4900 sq yds \n" ); document.write( "dimensions: 70 by 70 yds, a square. \n" ); document.write( " |