document.write( "Question 862757: David has 280 yards of fencing to enclose a rectangular area. Find the demensions of the rectangle that maximize the enclosed area.What is the maximum area? \n" ); document.write( "
Algebra.Com's Answer #519927 by lwsshak3(11628)\"\" \"About 
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David has 280 yards of fencing to enclose a rectangular area. Find the demensions of the rectangle that maximize the enclosed area.What is the maximum area?
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\n" ); document.write( "let x=width
\n" ); document.write( "let y=length
\n" ); document.write( "2x+2y=280
\n" ); document.write( "x+y=140
\n" ); document.write( "y=140-x)
\n" ); document.write( "..
\n" ); document.write( "Area=xy=x(140-x)=140x-x^2
\n" ); document.write( "=-x^2+140x
\n" ); document.write( "complete the square:
\n" ); document.write( "=-(x^2-140x+4900)+4900
\n" ); document.write( "=-(x-70)^2+4900
\n" ); document.write( "This is an equation of a parabola that opens down with vertex at (70,4900)
\n" ); document.write( "maximum area=4900 sq yds
\n" ); document.write( "dimensions: 70 by 70 yds, a square.
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