document.write( "Question 862758: a person can see the top of a building at an angle of 65 degrees the person is standing 50 ft away from the building and has an eye level of 5 ft how tall is the building to the nearest tenth of a foot \n" ); document.write( "
Algebra.Com's Answer #519926 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! a person can see the top of a building at an angle of 65 degrees the person is standing 50 ft away from the building and has an eye level of 5 ft how tall is the building to the nearest tenth of a foot. \n" ); document.write( "*** \n" ); document.write( "let x= distance from eye level to top of bldg. \n" ); document.write( "x/50=tan 65˚ \n" ); document.write( "x=tan 65˚*50 \n" ); document.write( "Height of building=x+5=tan 65˚*50+5=112.2 ft \n" ); document.write( " |