document.write( "Question 862159: Logx+log(x+3)=log10 \n" ); document.write( "

Algebra.Com's Answer #519913 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
Logx+log(x+3)=log10
\n" ); document.write( "solve for x:
\n" ); document.write( "log(x*(x+3))=log10
\n" ); document.write( "x^2+3x=10
\n" ); document.write( "x^2+3x-10=0
\n" ); document.write( "(x+5)(x-2)=0
\n" ); document.write( "x=-5(reject, x>0)
\n" ); document.write( "or
\n" ); document.write( "x=2 \n" ); document.write( "

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