document.write( "Question 862728: A box containing nickels, dimes, and quarters is worth a total of $2.10. There are twice as many dimes as quarters, and the number of nickels is two less than the number of dimes. How many of each coin are there? \n" ); document.write( "
Algebra.Com's Answer #519911 by ben720(159)![]() ![]() ![]() You can put this solution on YOUR website! Quarters * 25cents + Dimes * 10cents + Nickels * 5cents = $2.10 \n" ); document.write( "0.25Q+0.1D+0.05N=2.1 \n" ); document.write( " \n" ); document.write( "Let D = number of dimes \n" ); document.write( "Let quarters = D/2 \"There are twice as many dimes as quarters\" \n" ); document.write( "Let nickels = D-2 \"...the number of nickels is two less than the number of dimes.\" \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Distribute \n" ); document.write( " \n" ); document.write( "Add 1/10 to both sides. \n" ); document.write( " \n" ); document.write( "Convert the fractions to 80ths. \n" ); document.write( " \n" ); document.write( "Add the fractions \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( "There are 8 dimes, 4 quarters, and 6 nickels. \n" ); document.write( " |