document.write( "Question 862522: Mr. Wilson invested money in two accounts. His total investment was $20,000. If one account pays 7% in interest and the other pays 3% in interest, how much does he have in each account if he earned a total of $1,240 in interest in 1 year?\r
\n" ); document.write( "\n" ); document.write( "He invested $______ in the 7% account and $______ in the 3% account.
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Algebra.Com's Answer #519910 by mananth(16946)\"\" \"About 
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Part I 7.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 3.00% per annum ------------ Amount invested = y
\n" ); document.write( " 20000
\n" ); document.write( "Interest----- 1240.00
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\n" ); document.write( "Part I 7.00% per annum ---x
\n" ); document.write( "Part II 3.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 20000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "7.00% x + 3.00% y= 1240
\n" ); document.write( "Multiply by 100
\n" ); document.write( "7 x + 3 y= 124000.00 --------2
\n" ); document.write( "Multiply (1) by -7
\n" ); document.write( "we get
\n" ); document.write( "-7 x -7 y= -140000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -4 y= -16000
\n" ); document.write( "divide by -4
\n" ); document.write( " y = 4000
\n" ); document.write( "Part I 7.00% $ 16000
\n" ); document.write( "Part II 3.00% $ 4000
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\n" ); document.write( "CHECK
\n" ); document.write( "16000 --------- 7.00% ------- 1120.00
\n" ); document.write( "4000 ------------- 3.00% ------- 120.00
\n" ); document.write( "Total -------------------- 1240.00
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\n" ); document.write( "m.ananth@hotmail.ca
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