document.write( "Question 862659: Together, Grandma and Grandpa are 140 years old. How old is Grandma if Grandpa was twice as old as Grandma was when Grandpa was as old as Grandma is now. \n" ); document.write( "
Algebra.Com's Answer #519905 by ankor@dixie-net.com(22740)\"\" \"About 
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Together, Grandma and Grandpa are 140 years old.
\n" ); document.write( " How old is Grandma if Grandpa was twice as old as Grandma was when Grandpa was as old as Grandma is now.
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\n" ); document.write( "Let m = grandma's age
\n" ); document.write( "let p = grandpa's age
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\n" ); document.write( "Let d = the difference in their age d-m
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\n" ); document.write( "\"Together, Grandma and Grandpa are 140 years old.\"
\n" ); document.write( "p + m = 140
\n" ); document.write( "\" How old is Grandma if Grandpa was twice as old as Grandma was when Grandpa was as old as Grandma is now.
\n" ); document.write( "Write grandma's age as p-d
\n" ); document.write( "p - d = 2(p-d-d)
\n" ); document.write( "p - d = 2(p-2d)
\n" ); document.write( "p - d = 2p - 4d
\n" ); document.write( "4d - d = 2p - p
\n" ); document.write( "3d = p
\n" ); document.write( "Replace d with (p-m)
\n" ); document.write( "3(p-m) = p
\n" ); document.write( "3p - 3m = p
\n" ); document.write( "3p - p = 3m
\n" ); document.write( "3p = 3m
\n" ); document.write( "p = \"3%2F2\"m
\n" ); document.write( "p = 1.5m
\n" ); document.write( "Replace p with 1.5m in the first equation
\n" ); document.write( "1.5m + m = 140
\n" ); document.write( "2.5m = 140
\n" ); document.write( "m = 140/2.5
\n" ); document.write( "m = 56 yrs is Grandma's age
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\n" ); document.write( "Check this find Grandpa's age: 1.5(56) = 84 hrs old, 28 yrs apart
\n" ); document.write( "\"Grandpa was twice as old as Grandma was when Grandpa was as old as Grandma is now.\"
\n" ); document.write( "84 - 28 = 2(56 - 28)
\n" ); document.write( "56 = 2(28)\r
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