document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=9498>Question 9498</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello,<BR>\n" );
document.write( "I need help on my Algebra 2 homework. I tried different ways to reach an answer, but the answers I got doesn't make sense. The problem is: The width of a rectangle is 12 units less than its length. If you add 30 units to both the length and width, you double the perimeter. Find the length and width of the original rectangle. Please reply as soon as possible. I greatly appreciate your help and time.<BR>\n" );
document.write( "Julia </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5199 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5199\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = length of the rectangle<BR>\n" );
document.write( "x-12 = width of the rectangle<BR>\n" );
document.write( "2x + 2(x-12) = original perimeter<BR>\n" );
document.write( "2x + 2x - 24  or 4x - 24 = original perimeter\r<BR>\n" );
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document.write( "New rectangle<BR>\n" );
document.write( "x + 30 = new length<BR>\n" );
document.write( "x - 12 + 30 = x+ 18 = new width<BR>\n" );
document.write( "2(x+30) + 2 (x+ 18) = new perimeter<BR>\n" );
document.write( "2x + 60 + 2x + 36 or 4x + 96 = new perimeter\r<BR>\n" );
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document.write( "THE EQUATION:\r<BR>\n" );
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document.write( "New perimter = 2* original perimeter<BR>\n" );
document.write( "4x + 96 = 2( 4x - 24)<BR>\n" );
document.write( "4x + 96 = 8x - 48<BR>\n" );
document.write( "-4x = -144<BR>\n" );
document.write( "x= 36  = original length<BR>\n" );
document.write( "x - 12 = 36- 12 = 24 = original width\r<BR>\n" );
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document.write( "ANSWER:  Origianl rectangle is 24 by 36 \r<BR>\n" );
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document.write( "Check:  New perimeter = twice original perimeter:<BR>\n" );
document.write( "Perimeter = 2(36) + 2(24) = 72 + 48 = 120\r<BR>\n" );
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document.write( "New rectangle length = 36 + 30 = 66<BR>\n" );
document.write( "New rectangle width = 24 + 30 = 54 <BR>\n" );
document.write( "Perimeter = 2(66) + 2(54) = 132 + 108 = 140   \r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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