document.write( "Question 72694: 2 positive real numbers that differ by 1 and have a product of 1 \n" ); document.write( "
Algebra.Com's Answer #51984 by ankor@dixie-net.com(22740)\"\" \"About 
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2 positive real numbers that differ by 1 and have a product of 1
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\n" ); document.write( "Notice they didn't say that they were integers, just real, positive numbers.
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\n" ); document.write( "Let one number = x; the other number = (x+1)
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\n" ); document.write( "The product = 1
\n" ); document.write( "x(x+1) = 1
\n" ); document.write( "x^2 + x = 1
\n" ); document.write( "x^2 + x - 1 = 0; a quadratic equation
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\n" ); document.write( "Use the quadratic formula: a = 1; b = 1; c = -1
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1%5E2-4%2A1%2A-1+%29%29%2F%282%2A1%29+\"
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\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1-+%28-4%29%29%29%2F%282%29+\"
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\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1+%2B+4+%29%29%2F%282%29+\"
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\n" ); document.write( "\"x+=+%28-1+-+sqrt%28+5+%29%29%2F%282%29+\"
\n" ); document.write( "and
\n" ); document.write( "\"x+=+%28-1+%2B+sqrt%28+5+%29%29%2F%282%29+\"; they only want the positive number for x
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\n" ); document.write( "Check using decimals: \"x+=+%28-1+%2B+sqrt%28+5+%29%29%2F%282%29+\" = .618 rounded
\n" ); document.write( ".618(1.618) = .9999, close enough\r
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