document.write( "Question 862654: The length of a rectangle is 9 cm less than twice its width. If the area of the rectangle is 26 cm squared, what is the rectangles dimensions? \n" ); document.write( "
Algebra.Com's Answer #519809 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "A = Lw
\n" ); document.write( "26cm^2 = (2w-9cm)w | length = 9 cm less than twice its width
\n" ); document.write( " 2w^2 - 9w - 26 = 0
\n" ); document.write( " (2w -13)(w + 2) = 0 (Tossing out the negative solution for unit measure)
\n" ); document.write( " w = 13/2cm 0r 6.5cm and L = 4cm \"2%2813%2F2%29+-+9\"
\n" ); document.write( "CHECKING our answer***
\n" ); document.write( "\"6.5cm%2A4cm+=+26cm%5E2\"
\n" ); document.write( "Wish You the Best in your Studies.
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