document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=862564>Question 862564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1). Use the 1st principle to find the first derivative [f^'(x)] if<BR>\n" );
document.write( "G(x)=cosec2x at x=pi/6  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #519794 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=519794\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the 1st principle to find the first derivative [f^'(x)] if<BR>\n" );
document.write( "G(x)=cosec2x at x=pi/6<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "You didn't give f(x)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "If you want G'(x)<BR>\n" );
document.write( "G'(x) = -2csc(2x)*cot(2x)<BR>\n" );
document.write( "G'(pi/6) = -2*(2/sqrt(3))*(1/sqrt(3))<BR>\n" );
document.write( "= -4/3 </SPAN>\n" );
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