document.write( "Question 862633: An arrow is shot vertically upward from a platform 10 ft high at a rate of 185 ft per sec. When will the arrow hit the ground? Use the formula: h=16t^2+vt+h. (round off answer to the nearest tenth. Find seconds. \n" ); document.write( "
Algebra.Com's Answer #519771 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "h= -16t^2+185t+10, h = 0 when it hits the ground
\n" ); document.write( " 16t^2+185t+10 = 0
\n" ); document.write( "t = 11.6sec (to nearest tenth)
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"-16x%5E2%2B185x%2B10+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28185%29%5E2-4%2A-16%2A10=34865\".
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\n" ); document.write( " Discriminant d=34865 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-185%2B-sqrt%28+34865+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28185%29%2Bsqrt%28+34865+%29%29%2F2%5C-16+=+-0.0538036897701293\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28185%29-sqrt%28+34865+%29%29%2F2%5C-16+=+11.6163036897701\"
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\n" ); document.write( " Quadratic expression \"-16x%5E2%2B185x%2B10\" can be factored:
\n" ); document.write( " \"-16x%5E2%2B185x%2B10+=+-16%28x--0.0538036897701293%29%2A%28x-11.6163036897701%29\"
\n" ); document.write( " Again, the answer is: -0.0538036897701293, 11.6163036897701.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-16%2Ax%5E2%2B185%2Ax%2B10+%29\"
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