document.write( "Question 862576: What proportion of members spend less than 40 minutes at the gym?given a mean of 80 minutes and standard deviation of 20 \n" ); document.write( "

Algebra.Com's Answer #519733 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "mean of 80 minutes and standard deviation of 20
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document.write( "P( x< 40) = P(z < (40-80)/20 ) = P(z < -2)   invNorm(-2) = .0228  0r 2.28% \n" );
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