document.write( "Question 862473: A woman invested 4 times as much at 2% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $700. How much did she invest at each rate?\r
\n" ); document.write( "\n" ); document.write( "She invested $_____ in the 6% account and $_____ in the 2% account.
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Algebra.Com's Answer #519674 by mananth(16946)\"\" \"About 
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6%----------------x\r
\n" ); document.write( "\n" ); document.write( "2%----------------4x\r
\n" ); document.write( "\n" ); document.write( "Interest = 700 / year\r
\n" ); document.write( "\n" ); document.write( "6%x+2%(4x)=700\r
\n" ); document.write( "\n" ); document.write( "multiply equation by 100\r
\n" ); document.write( "\n" ); document.write( "6x+8x=70000\r
\n" ); document.write( "\n" ); document.write( "14x=70000\r
\n" ); document.write( "\n" ); document.write( "/14
\n" ); document.write( "x=5000\r
\n" ); document.write( "\n" ); document.write( "$5000 @ 6%
\n" ); document.write( "$20000 @ 2%
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