document.write( "Question 862473: A woman invested 4 times as much at 2% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $700. How much did she invest at each rate?\r
\n" );
document.write( "\n" );
document.write( "She invested $_____ in the 6% account and $_____ in the 2% account. \n" );
document.write( "
Algebra.Com's Answer #519674 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 6%----------------x\r \n" ); document.write( "\n" ); document.write( "2%----------------4x\r \n" ); document.write( "\n" ); document.write( "Interest = 700 / year\r \n" ); document.write( "\n" ); document.write( "6%x+2%(4x)=700\r \n" ); document.write( "\n" ); document.write( "multiply equation by 100\r \n" ); document.write( "\n" ); document.write( "6x+8x=70000\r \n" ); document.write( "\n" ); document.write( "14x=70000\r \n" ); document.write( "\n" ); document.write( "/14 \n" ); document.write( "x=5000\r \n" ); document.write( "\n" ); document.write( "$5000 @ 6% \n" ); document.write( "$20000 @ 2% \n" ); document.write( " |