document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=862374>Question 862374</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The point Q(-3,6) is on the terminal arm of an angle in standard position.  Determine the value of that angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #519655 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=519655\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The point Q(-3,6) is on the terminal arm of an angle in standard position. Determine the value of that angle.<BR>\n" );
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document.write( "Q is in QII where x is negative and y is positive.<BR>\n" );
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document.write( "Ans: arctan(-6/3) = arctan(-2) = -63.43 degrees<BR>\n" );
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document.write( "Ans: Since the angle is in QII, angle = 180-63.43 = 116.57 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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