document.write( "Question 862385: Find the intervals of increase and decrease. Use the first derivatives test to find the local maxima and minima. Graph.\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x%5E2-1%29%2F%28x%5E2%2B1%29\" \r
\n" ); document.write( "\n" ); document.write( "Derivative is \"4x%2F%28x%5E2%2B1%29%5E2\" I think
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Algebra.Com's Answer #519643 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Nope. Derivative is\r
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\n" ); document.write( "\n" ); document.write( "You need to use a combination of the quotient rule and the chain rule.\r
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\n" ); document.write( "\n" ); document.write( "1st derivative is equal to zero only when x = 0, hence the only extremum is at x = 0.\r
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\n" ); document.write( "\n" ); document.write( "Second derivative:\r
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\n" ); document.write( "\n" ); document.write( "Second derivative has the value 4 (> 0) at x = 0, hence the extremum is a minimum.\r
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\n" ); document.write( "\n" ); document.write( "The denominator of the original function has no real zeros, hence there are no vertical asymptotes to the graph of this function.\r
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\n" ); document.write( "\n" ); document.write( "I'll leave the graphing to you, but it sort of looks like a side view of an \"innie\" belly button with a minimum at (0,-1) and asymptotic to y = 1 as x increases or decreases without bound.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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\"The

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