document.write( "Question 862385: Find the intervals of increase and decrease. Use the first derivatives test to find the local maxima and minima. Graph.\r
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document.write( "Derivative is I think \n" );
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Algebra.Com's Answer #519643 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Nope. Derivative is\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You need to use a combination of the quotient rule and the chain rule.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1st derivative is equal to zero only when x = 0, hence the only extremum is at x = 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Second derivative:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Second derivative has the value 4 (> 0) at x = 0, hence the extremum is a minimum.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The denominator of the original function has no real zeros, hence there are no vertical asymptotes to the graph of this function.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll leave the graphing to you, but it sort of looks like a side view of an \"innie\" belly button with a minimum at (0,-1) and asymptotic to y = 1 as x increases or decreases without bound.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |