document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=9439>Question 9439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> , show  that   a  characterestic  polynomial  is  always  monic.\r<BR>\n" );
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document.write( "please  help  me   solving   the  above  problem.<BR>\n" );
document.write( "                   thank you<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5196 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  You should mention about your definition of characteristic polynomial.\r<BR>\n" );
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document.write( " Is it about a linear operator a square matrix, etc?\r<BR>\n" );
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document.write( " You cannot assume study the same material or textbook as you right now.\r<BR>\n" );
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document.write( " In general, char(T) or char(A) = det(xI - T) or det(xI - A)<BR>\n" );
document.write( " and very clearly the leading coefficient is 1 and so it is monic.\r<BR>\n" );
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document.write( " You may need to use similar matrices i.e. <BR>\n" );
document.write( " det(xI - A) = det(xI - P^-1 B P) = det(P^-1)det(xI - B) det(P)<BR>\n" );
document.write( " = det(xI - B)\r<BR>\n" );
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document.write( " Kenny </SPAN>\n" );
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