document.write( "Question 862027: Two boats travel on a river between two towns and have the same two constant speeds: a high speed downstream and a low speed upstream. Boat 1 leaves town A as boat 2 leaves town B. They pass each other 7 miles from town A, stop 4 minutes at their destinations, and pass again 9 miles from town A. What is the distance between the towns? \n" ); document.write( "
Algebra.Com's Answer #519594 by ankor@dixie-net.com(22740)\"\" \"About 
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Two boats travel on a river between two towns and have the same two constant speeds:
\n" ); document.write( "a high speed downstream and a low speed upstream.
\n" ); document.write( "Boat 1 leaves town A as boat 2 leaves town B.
\n" ); document.write( "They pass each other 7 miles from town A, stop 4 minutes at their destinations, and pass again 9 miles from town A.
\n" ); document.write( "What is the distance between the towns?
\n" ); document.write( ":
\n" ); document.write( "let d = distance between A & B
\n" ); document.write( ":
\n" ); document.write( "At first meeting
\n" ); document.write( "Boat 1 travels 7 mi
\n" ); document.write( "Boat 2 travels (d-7)
\n" ); document.write( "At 2nd meeting
\n" ); document.write( "Boat 1 travels: (d-7)+(d-9) = 2d-16
\n" ); document.write( "Boat 2 travels: 7 + 9 = 16 mi
\n" ); document.write( "let x = the upstream speed
\n" ); document.write( "let y = the downstream speed
\n" ); document.write( ":
\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( "First meeting
\n" ); document.write( "\"7%2Fx\" = \"%28%28d-7%29%29%2Fy\"
\n" ); document.write( "7y = x(d-7)
\n" ); document.write( "2nd meeting
\n" ); document.write( "\"%28%28d-7%29%29%2Fx\" + \"%28%28d-9%29%29%2Fy\" = \"7%2Fy\" + \"9%2Fx\"
\n" ); document.write( "mult by xy
\n" ); document.write( "y(d-7) + x(d-9) = 7x + 9y
\n" ); document.write( "dy - 7y + dx - 9x = 7x + 9y
\n" ); document.write( "dy + dx = 7x + 9x + 9y + 7y
\n" ); document.write( "d(x+y) = 16x + 16y
\n" ); document.write( "d(x+y) = 16(x+y)
\n" ); document.write( "divide both sides by (x+y)
\n" ); document.write( "d = 16 mi distance from A to B\r
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