document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=862247>Question 862247</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose the radius of a circle is equal to half the length of the side of a square. Find the ratio of the area of the circle to the area of the square  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #519575 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=519575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let r be the side length of the square and the radius of the circle.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28pi%2Ar%5E2%29%2F%284r%29 ALIGN=MIDDLE  ALT=\"%28pi%2Ar%5E2%29%2F%284r%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the ratio of areas, circle to the square.<BR>\n" );
document.write( "Simplified, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28pi%2Ar%2F4%29 ALIGN=MIDDLE  ALT=\"highlight%28pi%2Ar%2F4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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