document.write( "Question 72671: A rectangle scale used to weigh an elephant seal is 8 feet longer than it is wide. The area of the scale is 33 square feet. What are the dimensions of the scale? \n" ); document.write( "
Algebra.Com's Answer #51954 by Tutor Online(2)![]() ![]() ![]() You can put this solution on YOUR website! A rectangle scale used to weigh an elephant seal is 8 feet longer than it is wide. The area of the scale is 33 square feet. What are the dimensions of the scale?\r \n" ); document.write( "\n" ); document.write( "Let width be x feet \n" ); document.write( "Then length would be x+8 , as its given scale is 8 feet longer then its width\r \n" ); document.write( "\n" ); document.write( "Area of rectangle is given by\r \n" ); document.write( "\n" ); document.write( "Area= length * width \n" ); document.write( "Area of scale = x(x+8) sq feet\r \n" ); document.write( "\n" ); document.write( "x ( x+8 ) = 33\r \n" ); document.write( "\n" ); document.write( "x^2 +8x -33 =0\r \n" ); document.write( "\n" ); document.write( "Solving above quadratic by factorization\r \n" ); document.write( "\n" ); document.write( "x^2 + 11x -3x -33 =0 \n" ); document.write( "x(x+11) -3 ( x+11)=0 \n" ); document.write( "(x+11)(x-3) =0\r \n" ); document.write( "\n" ); document.write( "So either x = 3\r \n" ); document.write( "\n" ); document.write( "x = -11\r \n" ); document.write( "\n" ); document.write( "x cannot be negative as width cannot be negative so x = 3 is the answer\r \n" ); document.write( "\n" ); document.write( "So width of scale is 3 \n" ); document.write( "hope this helps \n" ); document.write( " \n" ); document.write( " |