document.write( "Question 862124: A and B play 12 games of chess of which 6 are won by A, 4 are won by B, 2 ends in a draw. They agree to play a tournament consisting of 3 games. Find the probability that (a) A wins all 3 games (b) two games end in a draw, (c) A and B win alternatively, (d) B wins atleast one games. \n" ); document.write( "
Algebra.Com's Answer #519535 by Fombitz(32388)\"\" \"About 
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Look at all the possible outcomes there are 3^3 or 27 of them.
\n" ); document.write( "AAA AAB AAD ABA ABB ABD ADA ADB ADD
\n" ); document.write( "BAA BAB BAD BBA BBB BBD BDA BDB BDD
\n" ); document.write( "DAA DAB DAD DBA DBB DBD DDA DDB DDD
\n" ); document.write( "A) \"P%28AAA%29=1%2F27\"
\n" ); document.write( "B) \"P%282D%29=5%2F27+\"
\n" ); document.write( "C) I assume that mean BAB ABD etc.,There are six of those (BAB,DAB,BAD,ABA,DBA,ABD) \"P=6%2F27=2%2F9\"
\n" ); document.write( "D) \"P%281B%29=19%2F27\"
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