document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=862063>Question 862063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone tell me where I am going wrong with trying to solve by elimination?\r<BR>\n" );
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document.write( "8x-3y=-6   \r<BR>\n" );
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document.write( "5x+6y=75   \r<BR>\n" );
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document.write( "5(8x-3y=-6)   40x-15y=-30<BR>\n" );
document.write( "               5x+6y=75<BR>\n" );
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document.write( "             35x-9y =45<BR>\n" );
document.write( "Then I am stuck! Do I divide by 35x by 35 and 45 by 35? I am so confused at the moment.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #519510 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=519510\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It would be easier to multiply the first 8x-3y=-6  by 2 and then add the new equation to the second equation 5x+6y=75 so that you eliminate y <BR>\n" );
document.write( "since -6y+6y=0<BR>\n" );
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