document.write( "Question 862167: solve by cross multiplication method
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document.write( "QUS: x is divided by a + y is divided by b is equal to a+b,this is first equation
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document.write( " & x is divided by square of a + y is divided by square of b is equal to two,
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document.write( " this is equation two \n" );
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Algebra.Com's Answer #519506 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Those already look crazy. Here is another try to understand:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Simplifying, \n" ); document.write( " \n" ); document.write( "Simplifying, \n" ); document.write( "- \n" ); document.write( "Continuing with this, these equations are both linear in x and y. That is assuming if a and b are taken as constants. \n" ); document.write( "System is: \n" ); document.write( "-------------------- \n" ); document.write( "bx+ay=ab(a+b) \n" ); document.write( "------------------- \n" ); document.write( "b^2x+a^2y=a(ab)^2 \n" ); document.write( "--------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Maybe use Elimination Method. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( "Next, to solve for x, you could either try elimination of y to solve for x, or you could try substituting what was just found for y into either system equation and solve for x. \n" ); document.write( "- \n" ); document.write( "Here is an attempt substituting. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |