document.write( "Question 862167: solve by cross multiplication method
\n" ); document.write( "QUS: x is divided by a + y is divided by b is equal to a+b,this is first equation
\n" ); document.write( " & x is divided by square of a + y is divided by square of b is equal to two,
\n" ); document.write( " this is equation two
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Algebra.Com's Answer #519506 by josgarithmetic(39617)\"\" \"About 
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\"%28x%2F%28a%2By%29%29%2Fb=a%2Bb\", your first equation;\r
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\n" ); document.write( "\n" ); document.write( "\"x%2F%28a%2By%29%5E2%2Fb%5E2=2\", your second equation.\r
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\n" ); document.write( "\n" ); document.write( "Those already look crazy. Here is another try to understand:\r
\n" ); document.write( "\n" ); document.write( "\"x%2Fa%2By%2Fb=a%2Bb\", your first equation;
\n" ); document.write( "Simplifying, \"bx%2Bay=ab%28a%2Bb%29\";
\n" ); document.write( "\"x%2Fa%5E2%2By%2Fb%5E2=2\", your second equation.
\n" ); document.write( "Simplifying, \"b%5E2%2Ax%2Ba%5E2y=2a%5E2b%5E2\".
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\n" ); document.write( "Continuing with this, these equations are both linear in x and y. That is assuming if a and b are taken as constants.
\n" ); document.write( "System is:
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\n" ); document.write( "bx+ay=ab(a+b)
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\n" ); document.write( "b^2x+a^2y=a(ab)^2
\n" ); document.write( "--------------------\r
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\n" ); document.write( "\n" ); document.write( "Maybe use Elimination Method.
\n" ); document.write( "\"b%2Abx%2Bb%2Aay=ab%5E2%28a%2Bb%29\", as first equation.
\n" ); document.write( "\"%28b%5E2x%2Ba%5E2y%29-%28b%5E2x%2Baby%29=a%28ab%29%5E2-ab%5E2%28a%2Bb%29\", subtracting first from second.
\n" ); document.write( "\"a%5E2y-aby=a%5E3%2Ab%5E2-ab%5E2%28a%2Bb%29\", the x term has been \"eliminated\".
\n" ); document.write( "\"%28a%5E2-ab%29y=a%5E3b%5E2-ab%5E2%28a%2Bb%29\"
\n" ); document.write( "\"y=%28a%5E3b%5E2-ab%5E2%28a%2Bb%29%29%2F%28a%5E2-ab%29\"
\n" ); document.write( "\"highlight%28y=%28a%5E2b%5E2-b%5E2%28a%2Bb%29%29%2F%28a-b%29%29\"
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\n" ); document.write( "Next, to solve for x, you could either try elimination of y to solve for x, or you could try substituting what was just found for y into either system equation and solve for x.
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\n" ); document.write( "Here is an attempt substituting.
\n" ); document.write( "\"b%5E2x%2Ba%5E2y=a%28ab%29%5E2\"
\n" ); document.write( "\"x%2Ab%5E2=a%5E3b%5E2-a%5E2y\"
\n" ); document.write( "\"x=%28a%5E3b%5E2-a%5E2y%29%2F%28b%5E2%29=a%5E3-%28a%2Fb%29%5E2%2Ay\"
\n" ); document.write( "\"x=a%5E3-%28a%2Fb%29%5E2%28%28a%5E2b%5E2-b%5E2%28a%2Bb%29%29%2F%28a-b%29%29\"... and then a bit of further work to simplify this.
\n" ); document.write( "\"x=a%5E3-a%5E2%28a%5E2-ab%29%2F%28a-b%29\"
\n" ); document.write( "\"x=a%5E3-a%5E3%28a-b%29%2F%28a-b%29\"
\n" ); document.write( "\"x=a%5E3-a%5E3%2A1\"
\n" ); document.write( "\"highlight%28x=0%29\"-----Interesting result.
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