document.write( "Question 862112: Find to the nearest degree, all values of X in the interval 0°≤X≤360° which satisfy the equation 3sin^2X+2sinX-1=0 \n" ); document.write( "
Algebra.Com's Answer #519479 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find to the nearest degree, all values of X in the interval 0°≤X≤360° which satisfy the equation 3sin^2X+2sinX-1=0 \n" ); document.write( "(3sinx-1)(sinx+1)=0 \n" ); document.write( ".. \n" ); document.write( "3sinx-1=0 \n" ); document.write( "sinx=1/3 \n" ); document.write( "x=20˚, 161˚ \n" ); document.write( ".. \n" ); document.write( "sinx+1=0 \n" ); document.write( "sinx=-1 \n" ); document.write( "x=270˚ \n" ); document.write( " |