document.write( "Question 862112: Find to the nearest degree, all values of X in the interval 0°≤X≤360° which satisfy the equation 3sin^2X+2sinX-1=0 \n" ); document.write( "
Algebra.Com's Answer #519479 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Find to the nearest degree, all values of X in the interval 0°≤X≤360° which satisfy the equation 3sin^2X+2sinX-1=0
\n" ); document.write( "(3sinx-1)(sinx+1)=0
\n" ); document.write( "..
\n" ); document.write( "3sinx-1=0
\n" ); document.write( "sinx=1/3
\n" ); document.write( "x=20˚, 161˚
\n" ); document.write( "..
\n" ); document.write( "sinx+1=0
\n" ); document.write( "sinx=-1
\n" ); document.write( "x=270˚
\n" ); document.write( "
\n" );