document.write( "Question 862097: at noon mike bikes toward sues home at 12 mph and sue bikes toward mikes home at 8 mph when will they meet if their homes are 30 miles apart
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Algebra.Com's Answer #519449 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Think of one of them moving at the sum of their
\n" ); document.write( "speeds and the other one standing still
\n" ); document.write( "Let \"+t+\" = the time in hours it takes for them to meet
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\n" ); document.write( "\"+30+=+%28+12+%2B+8+%29%2At+\"
\n" ); document.write( "\"+30+=+20t+\"
\n" ); document.write( "\"+t+=+1.5+\" hrs
\n" ); document.write( "They will meet at 1:30
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\n" ); document.write( "check:
\n" ); document.write( "Mike's equation:
\n" ); document.write( "\"+d%5B1%5D+=+12%2A1.5+\"
\n" ); document.write( "\"+d%5B1%5D+=+18+\" mi
\n" ); document.write( "and
\n" ); document.write( "\"+d%5B2%5D+=+8%2A1.5+\"
\n" ); document.write( "\"+d%5B2%5D+=+12+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+18+%2B+12+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+30+\" mi
\n" ); document.write( "OK\r
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