document.write( "Question 861558: X+Y=1
\n" ); document.write( "3X+5Y=12 \n" ); document.write( "

Algebra.Com's Answer #519366 by Fombitz(32388) $\"\"$ $\"About$

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$\"X%2BY=1\"$
\n" ); document.write( " $\"3X%2B5Y=12\"$
\n" ); document.write( "From eq. 1,
\n" ); document.write( " $\"X=1-Y\"$
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( " $\"3%281-Y%29%2B5Y=12\"$
\n" ); document.write( " $\"3-3Y%2B5Y=12\"$
\n" ); document.write( " $\"2Y=9\"$
\n" ); document.write( " $\"Y=9%2F2\"$
\n" ); document.write( "Then,
\n" ); document.write( " $\"X=1-9%2F2\"$
\n" ); document.write( " $\"X=2%2F2-9%2F2\"$
\n" ); document.write( " $\"X=-7%2F2\"$
\n" ); document.write( " \n" ); document.write( "

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